如何取得MSSQL中的存储过程的返回值

声明存储过程CREATE PROCEDURE sp_results_demo @InParmInt Int,@OutParmInt OUTPUTASBEGINSELECT 1,2,3,4SELECT uid,idFROM sysobjectsWHERE type='U'

SELECT @OutParmInt=69

Return 16END用于返回每个返回值时用PowerScrip如下：Long lReturn,lPram1,lPram2,lResult1,lResult2,lResult3,lResult4,lResult5,lResult6

DECLARE results_demo PROCEDURE FOR @returnValue=sp_results_demo @InParmInt = :lPram1, @OutParmInt = :lPram2 OUTPUT using sqlca;

execute results_demo;

Do While SQLCA.SQLCode=0Fetch results_demo INTO :lResult1,:lResult2,:lResult3,:lResult4 ;Loop

Fetch results_demo INTO :lResult5,:lResult6 ;

Do While sqlca.sqlcode=0Fetch results_demo Into :lResult5,:lResult6;Loop

Fetch results_demo Into :lReturn,:lPram2;

Close results_demo ;

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