数据库菜鸟不可不看 简单SQL语句小结

数据库菜鸟不可不看 简单SQL语句小结 - 应用软件 - 电脑教程网

数据库菜鸟不可不看 简单SQL语句小结

日期:2006-09-02   荐:

上当拉吧!~嘿嘿

1.在查询结果中显示列名:  a.用as关键字:select name as &acute;姓名&acute; from students order by age  b.直接表示:select name &acute;姓名&acute; from students order by age  2.精确查找:  a.用in限定范围:select * from students where native in (&acute;湖南&acute;, &acute;四川&acute;)   b.between...and:select * from students where age between 20 and 30  c.“=”:select * from students where name = &acute;李山&acute;   d.like:select * from students where name like &acute;李%&acute; (注意查询条件中有“%”,则说明是部分匹配,而且还有先后信息在里面,即查找以“李”开头的匹配项。所以若查询有“李”的所有对象,应该命令:&acute;%李%&acute;;若是第二个字为李,则应为&acute;_李%&acute;或&acute;_李&acute;或&acute;_李_&acute;。)  e.[]匹配检查符:select * from courses where cno like &acute;[AC]%&acute; (表示或的关系,与"in(...)"类似,而且"[]"可以表示范围,如:select * from courses where cno like &acute;[A-C]%&acute;)  3.对于时间类型变量的处理  a.smalldatetime:直接按照字符串处理的方式进行处理,例如:select * from students where birth > = &acute;1980-1-1&acute; and birth <= &acute;1980-12-31&acute;   4.集函数  a.count()求和,如:select count(*) from students (求学生总人数)  b.avg(列)求平均,如:select avg(mark) from grades where cno=’B2’  c.max(列)和min(列),求最大与最小  5.分组group  常用于统计时,如分组查总数:select gender,count(sno) from studentsgroup by gender(查看男女学生各有多少)  注意:从哪种角度分组就从哪列"group by"  对于多重分组,只需将分组规则罗列。比如查询各届各专业的男女同学人数 ,那么分组规则有:届别(grade)、专业(mno)和性别(gender),所以有"group by grade, mno, gender"select grade, mno, gender, count(*)from studentsgroup by grade, mno, gender  通常group还和having联用,比如查询1门课以上不及格的学生,则按学号(sno)分类有:select sno,count(*) from grades where mark<60group by snohaving count(*)>1   6.UNION联合  合并查询结果,如:SELECT * FROM studentsWHERE name like ‘张%’UNION [ALL]SELECT * FROM studentsWHERE name like ‘李%’  7.多表查询  a.内连接select g.sno,s.name,c.coursename from grades g JOIN students s ON g.sno=s.snoJOIN courses c ON g.cno=c.cno(注意可以引用别名)b.外连接b1.左连接select courses.cno,max(coursename),count(sno) from courses LEFT JOIN grades ON courses.cno=grades.cno group by courses.cno  左连接特点:显示全部左边表中的所有项目,即使其中有些项中的数据未填写完全。  左外连接返回那些存在于左表而右表中却没有的行,再加上内连接的行。  b2.右连接  与左连接类似  b3.全连接select sno,name,major from students FULL JOIN majors ON students.mno=majors.mno  两边表中的内容全部显示  c.自身连接select c1.cno,c1.coursename,c1.pno,c2.coursename from courses c1,courses c2 where c1.pno=c2.cno  采用别名解决问题。  d.交*连接select lastname firstname from lastname CROSS JOIN firstanme  相当于做笛卡儿积  8.嵌套查询  a.用关键字IN,如查询李山的同乡:select * from studentswhere native in (select native from students where name=’ 李山’)   b.使用关键字EXIST,比如,下面两句是等价的:select * from studentswhere sno in (select sno from grades where cno=’B2’)select * from students where exists (select * from grades where grades.sno=students.sno AND cno=’B2’)  9.关于排序order  a.对于排序order,有两种方法:asc升序和desc降序  b.对于排序order,可以按照查询条件中的某项排列,而且这项可用数字表示,如:select sno,count(*) ,avg(mark) from grades group by snohaving avg(mark)>85order by 3   10.其他  a.对于有空格的识别名称,应该用"[]"括住。  b.对于某列中没有数据的特定查询可以用null判断,如select sno,courseno from grades where mark IS NULL   c.注意区分在嵌套查询中使用的any与all的区别,any相当于逻辑运算“||”而all则相当于逻辑运算“&&”  d.注意在做否定意义的查询是小心进入陷阱:  如,没有选修‘B2’课程的学生 :select students.*from students, gradeswhere students.sno=grades.snoAND grades.cno <> ’B2’   上面的查询方式是错误的,正确方式见下方:select * from studentswhere not exists (select * from grades where grades.sno=students.sno AND cno=&acute;B2&acute;)   11.关于有难度多重嵌套查询的解决思想:  如,选修了全部课程的学生:select *from studentswhere not exists ( select *from courseswhere NOT EXISTS (select *from gradeswhere sno=students.snoAND cno=courses.cno))

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